Physics by Lamhi: Not Your Boring Physics

CLASS 11 · CHAPTER 1 · MEASUREMENT

Units and Measurements

Every physics answer is a number attached to a unit, measured with an instrument that has its own limits. This chapter is about respecting those limits, not just quoting formulas.

01 · See it

Watch it happen

Want the full chapter, section by section, with the SI unit table and every rounding rule spelled out? Read the detailed notes →
4.3 cm
Main scale reading
5
Coinciding division
0.05 cm
Vernier × LC
4.35 cm
Observed reading

Now suppose this particular caliper has a zero error:

Corrected length = observed reading − zero error = 4.35 cm − 0.00 cm = 4.35 cm

Drag the slider and watch which vernier line lines up with a main scale line. That single coincidence is the entire instrument: once you can read it, the “formula” below is just describing what your eyes already found.

02 · Derive it

Where the formula comes from

A standard vernier caliper divides its sliding scale into N=10N = 10 parts that together span 9 main scale divisions (MSD), so that:

N×VSD=(N−1)×MSD    ⇒    VSD=0.9 MSDN \times \text{VSD} = (N-1)\times\text{MSD} \;\;\Rightarrow\;\; \text{VSD} = 0.9\,\text{MSD}

The least count is just the gap this creates between one main scale division and one vernier division:

Least count
LC=MSD−VSD=MSDN=1 mm10=0.01 cm\textcolor{#e08a1e}{\text{LC}} = \text{MSD} - \text{VSD} = \dfrac{\text{MSD}}{N} = \dfrac{1\,\text{mm}}{10} = 0.01\,\text{cm}

Dimensional analysis uses the same kind of matching. To find how the time period of a simple pendulum depends on its length LL and gravity gg, assume a power-law form and match dimensions on both sides:

T=k Lagb    ⇒    [T1]=[L1]a[L1T−2]b=[La+bT−2b]T = k\,L^{a}g^{b} \;\;\Rightarrow\;\; [T^1] = [L^1]^{a}[L^1T^{-2}]^{b} = [L^{a+b}T^{-2b}]

Matching powers of TT gives −2b=1-2b = 1, so b=−12b = -\tfrac{1}{2}; matching powers of LL gives a+b=0a + b = 0, so a=12a = \tfrac{1}{2}:

T=kLg\textcolor{#e08a1e}{T} = k\sqrt{\dfrac{L}{g}}
03 · Break it

Where the shortcut stops working

That last derivation found the shape of the pendulum formula, the square root, the ratio of LL to gg, but it could not find the constant k=2πk = 2\pi. Dimensional analysis can never recover a pure number, because a pure number has no dimensions to match against. It’s why every dimensionally-derived formula in this course carries an unknown constant that has to come from somewhere else, usually a full derivation or an experiment.

The method has sharper limits too. It cannot handle a quantity that depends on the sum of two differently-scaled terms, like s=ut+12at2s = ut + \tfrac{1}{2}at^2: both terms already have the same dimension, so dimensional analysis alone could never have told you there should be a 12\tfrac{1}{2} in front of the second one, or even that the equation has two terms rather than one. And it breaks down completely for any relation built from a trigonometric, exponential, or logarithmic function, because the argument of sin⁡θ\sin\theta or exe^x has to be dimensionless in the first place, which dimensional analysis simply assumes rather than proves.

04 · Master it

Apply it under exam conditions

Q1. A vernier caliper with a least count of 0.01 cm has a main scale reading of 3.4 cm, with the 6th vernier division coinciding. The caliper has a zero error of +0.03 cm. Find the true length.

Observed=3.4+6×0.01=3.46 cm    ⇒    True length=3.46−0.03=3.43 cm\text{Observed} = 3.4 + 6\times0.01 = 3.46\text{ cm} \;\;\Rightarrow\;\; \text{True length} = 3.46 - 0.03 = \textcolor{#e08a1e}{3.43\text{ cm}}

Q2. Check whether v2=u2+2asv^2 = u^2 + 2as is dimensionally consistent.

Every term must reduce to [L2T−2][L^2T^{-2}]: [v2]=[LT−1]2=[L2T−2][v^2] = [LT^{-1}]^2 = [L^2T^{-2}], and [2as]=[LT−2][L]=[L2T−2][2as] = [LT^{-2}][L] = [L^2T^{-2}]. All three terms match, so the equation is dimensionally consistent, though (as above) that alone doesn’t prove the factor of 22 is correct.

05 · FAQs

Quick answers

What is least count?+

The smallest change in a quantity that a given instrument can actually detect. For a standard vernier caliper it's 0.01 cm, set entirely by how finely the vernier scale is divided against the main scale.

Why does a zero error need to be subtracted, not added?+

It depends on the sign. A positive zero error means the instrument over-reads, so you subtract it; a negative zero error means it under-reads, so subtracting a negative number effectively adds the missing length back. One rule, corrected = observed − zero error, handles both once the sign is right.

Can dimensional analysis prove a formula is correct?+

No, only that it isn't obviously wrong. It can never recover a pure numerical constant, and it can't distinguish between two dimensionally identical but physically different formulas.

What's the difference between accuracy and precision?+

Accuracy is how close a measurement is to the true value; precision is how consistent repeated measurements are with each other. An instrument can be very precise while still being consistently wrong, which is inaccurate.

Why do significant figures matter?+

Because they honestly report how well you actually know a number. Writing more digits than your instrument can justify claims a precision the measurement doesn't have.

Related concepts

Physics doesn’t stay inside chapter boundaries. Neither should you.